[idvdevelopers] ISL scripting

• To: <idvdevelopers@xxxxxxxxxxxxxxxx>
• Subject: [idvdevelopers] ISL scripting
• From: "Jun Chen" <jchen@xxxxxxxxxx>
• Date: Tue, 6 Apr 2010 10:03:46 -0700

Following that example isl file multiplefiles.isl:

<isl offscreen="false">
   <fileset  pattern=".*\.nc">
     <echo message="File: ${file}"/>
     <bundle file="${islpath}/test.xidv">
<!-- This sets the data file in the bundle to the ${file} -->
        <setfiles datasource=".*" file="${file}"/>
     </bundle>
     <pause seconds="20"/>
   </fileset>
</isl>

I want to dynamically generate each image file based on each file
${file}, but that file contains path and link from a location I only
have read permission, my question is:

How can I extract the (only) file name (without file extension) from
${file}?
Say ${file}="/myserver/mydirectory/myfile1.nc"

Is there any way I can extract just myfile1 from ${file}?

So I can add:

<image file="${islpath}/${myfilename}.png" />

Above, ${myfilename} should change corresponding to ${file}

Please help.

I am new to IDV, and found it's very useful, but poor documentation.


-jun

• Follow-Ups:
  • Re: [idvdevelopers] ISL scripting
    • From: jeff mcwhirter
  • Re: [idvdevelopers] ISL scripting
    • From: Stuart Wier