Re: 3D plot...(x->y)->z

[Bill Hibbard <billh@xxxxxxxxxxxxx>]

Hi Rakesh,

>          I think i made a mistake in presenting the function... The function 
> is
> (x , x->y) -> z.
>             y is a function of x
>             z is a function of x and y

This would have the MathType:

  ((x -> y), ((x, y) -> z))

However, it is odd that y occurs as both a dependent
variable (in (x -> y)) and an independent variable
(in ((x, y) -> z)).

Cheers,
Bill