> The x-values are in samples[0] and the y-values are in samples[1];
>
> Let you DEM be
>
> 3.3 x x
> north 2.7 x
>
> 1.3 x x x
> 0.2 0.3 1.1 1.2
> east
>
> Sampled points are represented bx "x".
>
> You've got lenX = 3, lenY = 2, and, thus, must input 6 pairs of
> coordinates.
> So, samples is (something like): samples[0]={0.2,1.1,1.2, 0.2,0.3,1.2};
> // east, or x values
> and samples[1]={1.3,1.3,1.3, 3.3,2.7,3.3}; //
> north, or y values
>
Hi Ugo, I am getting confused, I tried to implement the above,
//double[][] coords = new double[2][east.length];
coords[0] = new double[east.length];
coords[1] = new double[north.length];
for (int i=0;i<coords[0].length;i++) {
coords[0][i]=east[i];
coords[1][i]=north[i];
}
for (int j=0;j<coords[0].length;j++) {
System.out.println("e "+coords[0][j]);
}
for (int j=0;j<coords[1].length;j++) {
System.out.println("n "+coords[1][j]);
}
and they look like your samples[0] and samples[1]
now you are saying i have an array double[2][east*north], that would be
3*4 in your example?
How would I fill this array?
Sorry, I am just feeling stupid, I do not get that!
Thanks Desiree
